AP Physics 1 / Topic

Energy and Momentum of Rotating Systems

Unit 6 covers rotational kinetic energy, rolling without slipping, angular momentum, and its conservation - including collisions that make things spin and the classic spinning-skater scenario.

47 practice questions3 FRQs6 skill areas

What the exam asks

  • Split the kinetic energy of rolling objects into translational and rotational parts
  • Race rolling shapes down inclines using energy partition arguments
  • Apply the rolling constraint linking v and ω
  • Compute angular momentum for spinning objects and moving point masses
  • Use conservation of angular momentum when net external torque is zero (skaters, rotational collisions)

Key formulas and rules

Rotational KE

KE(rot) = ½Iω²; rolling total: ½mv² + ½Iω²

Rolling constraint

v = rω (no slipping)

Rolling race rule

smaller I/(mr²) reaches the bottom first (sphere beats disk beats hoop)

Angular momentum

L = Iω; point mass: L = mvr (perpendicular distance)

Conservation

no external torque ⇒ I1ω1 = I2ω2 (arms pulled in ⇒ spin faster)

Question bank breakdown

Multiple choice

47

Free response

3

Difficulty mix

10 easy · 26 medium · 11 hard

Skills covered

Translational and Rotational EnergyRolling Without SlippingAngular MomentumRotational Kinetic EnergyConservation of Energy with RotationAngular Momentum Conservation in Collisions

Every question in the bank comes with a worked explanation, and most add a per-choice breakdown so you learn why each wrong answer is wrong - not just the key.

Sample question

From the free tier of the ScoreMint AP Physics 1 bank - try it, then check the answer.

A thin hoop and a solid disk have the same mass MM and the same radius RR. Both start from rest at the top of an inclined plane and roll without slipping to the bottom. Which object reaches the bottom first, and why?

  • A. The hoop reaches the bottom first because it has a larger rotational inertia and therefore more angular momentum.
  • B. The solid disk reaches the bottom first because a smaller fraction of its kinetic energy is rotational.
  • C. They reach the bottom at the same time because they have the same mass and radius.
  • D. The hoop reaches the bottom first because circular shapes roll more efficiently.
Show answer and explanation

Answer: B. When rolling without slipping, gravitational PE converts to both translational and rotational KE: Mgh=12Mv2+12Iω2Mgh = \frac{1}{2}Mv^2 + \frac{1}{2}I\omega^2. With v=Rωv = R\omega, the solid disk (I=12MR2I = \frac{1}{2}MR^2) gets v=4gh3v = \sqrt{\frac{4gh}{3}}, while the hoop (I=MR2I = MR^2) gets v=ghv = \sqrt{gh}. The disk is faster because a smaller fraction of energy is tied up in rotation. Objects with smaller I/MR2I/MR^2 ratios always win the race down the incline.

Study tip

When a mass sticks to a rotating rod or disk, conserve angular momentum, never linear momentum or energy - the axle supplies external forces but no torque about itself.